NCERT Solutions for Class 10 Maths Exercise 3.1 (NEW SYLLABUS)

1. Form the pair of linear equations in the following problems, and find their solutions graphically.

(i) 10 students of class X took part in a mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.

(ii) 5 pencils and 7 pens together cost Rs 50, whereas 7 pencils and 5 pens together cost Rs. 46. Find the cost of one pencil and that of one pen.

Answer:

(i) Let number of boys = x

Let number of girls = y

According to given conditions, we have

x + y = 10

And, x = 10 – y

putting y=0,5,10,we get,
X=10-0=10
X=10-5=5,
X=10-10=0

x1050
y0510

Number of girls is 4 more than number of boys ……..Given,
so,
Y=x+4
putting x=-4,0,4 we get,
Y=-4+4=0
Y=0+4
Y=4+4=8

x-404
y048
https://images.topperlearning.com/topper/bookquestions/60_img13_3.1.JPG

We plot the points for both of the equations to find the solution.

(ii)

Let the cost of one pencil=Rs.X
and Let the cost of one pen=Rs.Y
According to the given conditions, we have:
=5x + 7y = 50
=5x=50-7y
=x=10-7/5y
https://images.topperlearning.com/topper/bookquestions/60_img13_3.1.JPG
Three solutions of this equation can be written in a table as follows:

x3-4-11
y51015


chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2
Three solutions of this equation can be written in a table as follows:

x024
y9.26.43.6

The graphical representation is as follows:
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2
 

2. On comparing the ratios a1/a2,b1/b2 and c1/c2 , find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:

(i) 5x − 4y + 8 = 0

(ii)9x + 3y + 12 = 0

7x + 6y – 9 = 018x + 6y + 24 = 0

(iii) 6x − 3y + 10 = 0

2x – y + 9 = 0

Answer:

(i) 5x − 4y + 8 = 0, 7x + 6y – 9 = 0

Comparing equation 5x − 4y + 8 = 0 with a1x + b1y + c1 = 0and 7x + 6y – 9 = 0 with a2x + b2y + c2 = 0,

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

we find that,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image017.png

(ii) 9x + 3y + 12 = 0, 18x + 6y + 24 = 0

Comparing equation 9x + 3y + 12 = 0 with a1x + b1y + c1 = 0and 7x + 6y – 9 = 0 with a2x + b2y + c2 = 0,

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image021.png

Hence
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image023.png

We find that,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image024.png

Hence, lines are coincident.

(iii) 6x − 3y + 10 = 0, 2x – y + 9 = 0

Comparing equation 6x − 3y + 10 = 0 with a1x + b1y + c1 = 0and 7x + 6y – 9 = 0 with a2x + b2y + c2 = 0,

We get, chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image021.png

Hence
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image023.png

We find that,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image024.png

Hence,
lines are parallel to each other.

3. On comparing the ratios a1/a2,b1/b2 and c1/c2 , find out whether the following pair of linear equations are consistent, or inconsistent.

(i) 3x + 2y = 5, 2x − 3y = 8

(ii) 2x − 3y = 7, 4x − 6y = 9

(iii) 3x/2 + 5y/3 = 7, 9x − 10y = 14

(iv) 5x − 3y = 11, −10x + 6y = −22

Answer:

(i) 3x + 2y = 5, 2x − 3y = 7

Comparing equation 3x + 2y = 5 with a1x + b1y + c1 = 0and 7x + 6y – 9 = 0 with a2x + b2y + c2 = 0,

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image036.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore,these linear equations will intersect at one point only and have only one possible solution.
And,pair of linear euations is consistent

(ii) 2x − 3y = 8, 4x − 6y = 9

Comparing equation 2x − 3y = 8 with a1x + b1y + c1 = 0and 7x + 6y – 9 = 0 with a2x + b2y + c2 = 0,

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore,these linear equations are parallel to each other and have no possible solution.in
And,pair of linear euations is inconsistent

(iii) chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image042.png9x − 10y = 14

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore, these linear equations will intersect each other at one point and have only one possible solution.
And,pair of linear euations is consistent

(iv) 5x − 3y = 11, −10x + 6y = −22

Comparing equation 5x − 3y = 11 with a1x + b1y + c1 = 0and 7x + 6y – 9 = 0 with a2x + b2y + c2 = 0,

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore these pair of lines have infinite number of solutions
And,pair of linear euations is consistent

4. Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically:

4. (i) x + y = 5, 2x + 2y = 10

(ii) x – y = 8, 3x − 3y = 16

(iii) 2x + y = 6, 4x − 2y = 4

(iv) 2x − 2y – 2 = 0, 4x − 4y – 5 = 0

Answer:

(i) x + y = 5, 2x + 2y = 10

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

(ii) x – y = 8, 3x − 3y = 16

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution.
Hence,the pair of linear equations is inconsistent.

(iii) 2x + y = 6, 4x − 2y = 4

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution.
Hence,the pair of linear equations is consistent

chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

(iv) 2x − 2y – 2 = 0, 4x − 4y – 5 = 0

We get,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

Therefore, these linear equations are parallel to each other and have no possible solution,
Hence,the pair of linear equations is inconsistent.

5. Half the perimeter of a rectangle garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

Answer:

Let width of rectangular garden = x metres
and length=y

So,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png

Hence, the graphic representation is as follows.
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

6. Given the linear equation (2x + 3y – 8 = 0), write another linear equation in two variables such that the geometrical representation of the pair so formed is:

(i) Intersecting lines

(ii) Parallel lines

(iii) Coincident lines

Answer:

(i) Let the second line be equal to a2x + b2y + c2 = 0,

Intersecting Lines:For this Condition,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png
The Second line such that it is intersecting the given line is
2x+4y-6=0

As,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

(ii) Let the second line be equal to a2x + b2y + c= 0,

parallel Lines:
For this Condition,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png
Hence,the second line can be 4x+6y-8=0

As,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

(iii) Let the second line be equal to a2x + b2y + c= 0,

Coincident lines: For coincident lines,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image035.png
Hence,the second line can be 6x+9y-24=0

As,
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image016.png

7. Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.

Answer:

For equation x – y + 1 = 0, we have following points which lie on the line

chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image070.png

For equation 3x + 2y – 12 = 0, we have following points which lie on the line

chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image071.png
chapter 3-Pair of Linear Equations in Two Variables Exercise 3.2/image072.jpg

We can see from the graphs that points of intersection of the lines with the x–axis are (–1, 0), (2, 3) and (4, 0).

CHAPTER NAMEOLD NCERTNEW NCERT 
Real NumbersEXERCISE 1.1 
EXERCISE 1.21.1CLICK HERE
EXERCISE 1.31.2CLICK HERE
EXERCISE 1.4
PolynomialsEXERCISE 2.12.1CLICK HERE
EXERCISE 2.22.2CLICK HERE
EXERCISE 2.3
EXERCISE 2.4
Pair of Linear Equations in Two VariablesEXERCISE 3.1
EXERCISE 3.23.1CLICK HERE
EXERCISE 3.33.2CLICK HERE
EXERCISE 3.43.3CLICK HERE
EXERCISE 3.5
EXERCISE 3.6
EXERCISE 3.7
Quadratic EquationsEXERCISE 4.14.1CLICK HERE
EXERCISE 4.24.2CLICK HERE
EXERCISE 4.3
EXERCISE 4.44.3CLICK HERE
Arithmetic ProgressionsEXERCISE 5.15.1CLICK HERE
EXERCISE 5.25.2CLICK HERE
EXERCISE 5.35.3CLICK HERE
EXERCISE 5.45.4 (Optional)CLICK HERE
TrianglesEXERCISE 6.16.1CLICK HERE
EXERCISE 6.26.2CLICK HERE
EXERCISE 6.36.3CLICK HERE
EXERCISE 6.4
EXERCISE 6.5
EXERCISE 6.6
Coordinate GeometryEXERCISE 7.17.1CLICK HERE
EXERCISE 7.27.2CLICK HERE
EXERCISE 7.3
EXERCISE 7.4
Introduction to TrigonometryEXERCISE 8.18.1CLICK HERE
EXERCISE 8.28.2CLICK HERE
EXERCISE 8.3
EXERCISE 8.48.3CLICK HERE
Some Applications of TrigonometryEXERCISE 9.19.1CLICK HERE
CirclesEXERCISE 10.110.1CLICK HERE
EXERCISE 10.210.2CLICK HERE
Construction
Areas Related to CirclesEXERCISE 12.1
EXERCISE 12.211.1CLICK HERE
EXERCISE 12.3
Surface Areas and VolumesEXERCISE 13.112.1CLICK HERE
EXERCISE 13.212.2CLICK HERE
EXERCISE 13.3
EXERCISE 13.4
EXERCISE 13.5
StatisticsEXERCISE 14.113.1CLICK HERE
EXERCISE 14.213.2CLICK HERE
EXERCISE 14.313.3CLICK HERE
EXERCISE 14.4
ProbabilityEXERCISE 15.114.1CLICK HERE
EXERCISE 15.2

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