NCERT Solutions for Class 10 Maths Exercise 12.2 (NEW SESSION)

Solve the followings Questions.

1. The following table shows the ages of the patients admitted in a hospital during a year:

Age (in years)5-1515-2525-3535-4545-5555-65
Number of patients6112123145

Find the mode and the mean of the data given above. Compare and interpret the two
measures of central tendency.


Answer:

To find out the modal class, let us the consider the class interval with high frequency

Here, the greatest frequency = 23, so the modal class = 35 – 45,

l = 35,

class width (h) = 10,

fm = 23,

f1 = 21 and f2 = 14

The formula to find the mode is

Mode = l+ [(fm-f1)/(2fm-f1-f2)]×h

Substitute the values in the formula, we get

Mode = 35+[(23-21)/(46-21-14)]×10

Mode = 35+(20/11) = 35+1.8

Mode = 36.8 year

So the mode of the given data = 36.8 year

Calculation of Mean:

First find the midpoint using the formula, x= (upper limit +lower limit)/2

The mean formula is

Mean = x̄ = ∑fixi /∑fi

= 2830/80

= 35.37 years

Therefore, the mean of the given data = 35.37 years.

2. The following data gives the information on the observed lifetimes (in hours) of 225 electrical components :

Lifetime (in hours)0-2020-4040-6060-8080-100100-120
Frequency103552613829

Determine the modal lifetimes of the components.

Answer:

Given:

From the given data the modal class is 60–80.

l = 60,

The frequencies are:

fm = 61, f1 = 52, f2 = 38 and h = 20

The formula to find the mode is

Mode = l+ [(fm-f1)/(2fm-f1-f2)]×h

Substitute the values in the formula, we get

Mode =60+[(61-52)/(122-52-38)]×20

Mode = 60+((9 x 20)/32)

Mode = 60+(45/8) = 60+ 5.625

Therefore, modal lifetime of the components = 65.625 hours.

3. The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure :

ExpenditureNumber of families
1000-150024
1500-200040
2000-250033
2500-300028
3000-350030
3500-400022
4000-450016
4500-50007

Answer:

For Mode:

Given data:

Modal class = 1500-2000,

l = 1500,

Frequencies:

fm = 40 f1 = 24, f2 = 33 and

h = 500

Mode formula:

Mode = l+ [(fm-f1)/(2fm-f1-f2)]×h

Substitute the values in the formula, we get

Mode =1500+[(40-24)/(80-24-33)]×500

Mode = 1500+((16×500)/23)

Mode = 1500+(8000/23) = 1500 + 347.83

Therefore, modal monthly expenditure of the families = Rupees 1847.83

Calculation for mean:

First find the midpoint using the formula, x=(upper limit +lower limit)/2

Let us assume a mean, A be 2750

chapter 14-Statistics Exercise 14.2/image002.png

The formula to calculate the mean,

Mean = x̄ = a +(∑fiui /∑fi)×h

Substitute the values in the given formula

= 2750+(-35/200)×500

= 2750-87.50

= 2662.50

So, the mean monthly expenditure of the families = Rupees 2662.50

4. The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.

chapter 14-Statistics Exercise 14.2/image030.png

Answer:

chapter 14-Statistics Exercise 14.2/image002.png
chapter 14-Statistics Exercise 14.2/image031.png

5. The given distribution shows the number of runs scored by some top batsmen of the world in one-day cricket matches:

chapter 14-Statistics Exercise 14.2/image038.png

Find mode of the data.

Answer:

chapter 14-Statistics Exercise 14.2/image002.png

6. A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarized it in the table given below:

chapter 14-Statistics Exercise 14.2/image044.png

Find the mode of the data.

Answer:

chapter 14-Statistics Exercise 14.2/image002.png
CHAPTER NAMEOLD NCERTNEW NCERT 
Real NumbersEXERCISE 1.1 
EXERCISE 1.21.1CLICK HERE
EXERCISE 1.31.2CLICK HERE
EXERCISE 1.4
PolynomialsEXERCISE 2.12.1CLICK HERE
EXERCISE 2.22.2CLICK HERE
EXERCISE 2.3
EXERCISE 2.4
Pair of Linear Equations in Two VariablesEXERCISE 3.1
EXERCISE 3.23.1CLICK HERE
EXERCISE 3.33.2CLICK HERE
EXERCISE 3.43.3CLICK HERE
EXERCISE 3.5
EXERCISE 3.6
EXERCISE 3.7
Quadratic EquationsEXERCISE 4.14.1CLICK HERE
EXERCISE 4.24.2CLICK HERE
EXERCISE 4.3
EXERCISE 4.44.3CLICK HERE
Arithmetic ProgressionsEXERCISE 5.15.1CLICK HERE
EXERCISE 5.25.2CLICK HERE
EXERCISE 5.35.3CLICK HERE
EXERCISE 5.45.4 (Optional)CLICK HERE
TrianglesEXERCISE 6.16.1CLICK HERE
EXERCISE 6.26.2CLICK HERE
EXERCISE 6.36.3CLICK HERE
EXERCISE 6.4
EXERCISE 6.5
EXERCISE 6.6
Coordinate GeometryEXERCISE 7.17.1CLICK HERE
EXERCISE 7.27.2CLICK HERE
EXERCISE 7.3
EXERCISE 7.4
Introduction to TrigonometryEXERCISE 8.18.1CLICK HERE
EXERCISE 8.28.2CLICK HERE
EXERCISE 8.3
EXERCISE 8.48.3CLICK HERE
Some Applications of TrigonometryEXERCISE 9.19.1CLICK HERE
CirclesEXERCISE 10.110.1CLICK HERE
EXERCISE 10.210.2CLICK HERE
Construction
Areas Related to CirclesEXERCISE 12.1
EXERCISE 12.211.1CLICK HERE
EXERCISE 12.3
Surface Areas and VolumesEXERCISE 13.112.1CLICK HERE
EXERCISE 13.212.2CLICK HERE
EXERCISE 13.3
EXERCISE 13.4
EXERCISE 13.5
StatisticsEXERCISE 14.113.1CLICK HERE
EXERCISE 14.213.2CLICK HERE
EXERCISE 14.313.3CLICK HERE
EXERCISE 14.4
ProbabilityEXERCISE 15.114.1CLICK HERE
EXERCISE 15.2

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